Solution

 The total number of ways of selecting 3 stocks from 5 stocks is given by 

$C_3^5$.

Number of ways of selecting two profitable stocks when 3 stocks are selected is given by number of ways one can choose 2 stocks from 3 profitable stocks and 1 stock from 3 non-profitable stocks i.e. $C_2^2 C_1^3.$

Since, stocks are chosen at random, probability that she selects two profitable stocks is given by $\dfrac{C_2^2C_1^3}{C_3^5}= \dfrac{3}{10}.$

Number of ways of selecting one profitable stock when 3 stocks are selected is given by number of ways one can choose 1 stock from 2 profitable stocks and choose 2 stocks from 3 non-profitable stock i.e. $C_1^2 C_2^3.$

Since, stocks are chosen at random, probability that she selects one profitable stock is given by $\dfrac{C_1^2C_2^3}{C_3^5}= \dfrac{3}{5}.$

$Answer$

3/10; 3/5