Solution

Engineering Mechanics (Dynamics)

Chapter 12

Exercise 195

$$v_B=v_0+a_{D}t$$

$$v_B = 0 + (5\mathrm{~m/s}^2)(1.07\mathrm{~s}) = 5.35\mathrm{~m/s}$$

Applying the relative-velocity equation in scalar form since the velocity vectors of both blocks are parallel; along the $x$-coordinate axis, as shown in the Fig.

$$v_A=v_B+v_{A/B}$$

$$0.613\mathrm{~m/s} = -5.35\mathrm{~m/s} + v_{A/B}$$

$$\boxed{\color{#4257b2}v_{A/B} = +5.963\mathrm{~m/s} = 5.963\mathrm{~m/s}\;\rightarrow}$$

$\overset{+}\rightarrow$