Solution Let AA and BB be the event that smoke is detected by device AA and BB, respectively.Given: If smoke is present,P(A)= 0.95, ~~P(B)= 0.98, ~~ P(A \cap B) = 0.94P(A)=0.95, P(B)=0.98, P(A∩B)=0.94Answera. 0.99 b 0.01