The total number of simple events is
The number of ways in which no one has birthday on same date is given by Note that event
Answer
The total number of simple events is
(365)n.
The number of ways in which no one has birthday on same date is given by Pn365. Note that event B=Ac.
\begin{align*} P(A)&= \dfrac{\textrm{No. of simple events in A}}{\textrm{Total number of simple events}}\\ &= \dfrac{P_n^{365}}{(365)^n}\\\\ P(B)&= 1 - P(A)\\ &= 1- \dfrac{P_n^{365}}{(365)^n} \end{align*}P(A)P(B)=Total number of simple eventsNo. of simple events in A=(365)nPn365=1−P(A)=1−(365)nPn365