Solution

 

(a) The distribution is roughly symmetric, because most of the data values lie in the middle of the stem and leaf plot.

There are no outliers visible, because there are no gaps in the stem and leaf plot.

(b) The smallest observation is given at the top of the stem-and-leaf plot.

Since the first row of the stem and leaf plot is "1 $|$ 6 8", the first data value is represented by $1 | 6$. Since the stem represents the ones and the leaf represents the tenths, $1 | 6$ represents the data value 1.6.

(c) Since the last row of the stem and leaf plot contain only 2 data values, they represents the two largest observations and thus the eight and ninth largest observations are not in the last row of the stem and leaf plot. The second to last row of the stem and leaf plot contains 5 data values, which thus represent the third to seventh largest observation.

The last two digits in the third to last row of the stem and leaf plot then represent the eighth and ninth largest observation. Thus the eighth and ninth largest observation are both represented by $4 | 9$. Since the stem represents the ones and the leaf represents the tenths, $4 | 9$ represents the data value 4.9 and thus the eighth and ninth largest observation are both 4.9.

Answer

(a) Roughly symmetric, No outliers

(b) 1.6

(c) 4.9

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