Solution Let R_MRM and R_WRW be the event that a man and woman, respectively, remains in particular company for 10 years or more.Given: P(R_M)=P(R_W)= \dfrac{1}{6}P(RM)=P(RW)=61a.\begin{align*} P(R_M^c)&= 1 - P(R_M)\\ &= 1- \dfrac{1}{6}\\ &= \dfrac{5}{6} \end{align*}P(RMc)=1−P(RM)=1−61=65Answera. \dfrac{5}{6}65 b. \dfrac{25}{36}3625 c. \dfrac{11}{36}3611