Exercise 4.70
(P4.70)- Bayes’ Rule II If an experiment is conducted, one and only one of three mutually exclusive events S1, S2, and S3 can occur, with these probabilities:
P(S1) = .2 P(S2) = .5 P(S3) = .3
The probabilities of a fourth event A occurring, given that event S1, S2, or S3 occurs, are
P(A|S1) = .2 P(A|S2) = .1 P(A|S3) = .3
If event A is observed, find P(S1|A), P(S2|A), and P(S3|A).
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